Zmija na bajsu


Otkleni vo:
1. Izračunaj.

(a) \( \left(-\frac{-3.20}{1.90}\right) \cdot \left(-\frac{-3.20}{1.90}\right) \cdot \left(\frac{1}{2.60}\right) \cdot \left(\frac{1}{2.60}\right) \)

(b) \( \left(\frac{3.50}{3.70}\right) \cdot \left(\frac{3.50}{3.70}\right) \cdot \frac{1}{2} \cdot \frac{40}{46 \cdot 46} \)

(c) \( \left(-\frac{0.60}{3.70 \cdot 3.70}\right) \cdot \left(-\frac{0.60}{3.70 \cdot 3.70}\right) - \left(-\frac{8}{2.40}\right) \cdot \left(-\frac{8}{2.40}\right) \)

(d) \( \frac{1}{8} \cdot \left(\frac{1}{9}\right) \cdot \left(\frac{1}{9}\right) - \frac{1}{8 \cdot 8} \)

(e) \( \frac{1}{5} \cdot \frac{1}{3 \cdot 3} \cdot \frac{8 \cdot 8}{12} \)

(f) \( \frac{5}{2.10} \cdot \left(\frac{6.60}{9}\right) \cdot \left(\frac{6.60}{9}\right) \cdot \frac{9}{4.60} \)

(g) \( \left(\frac{5}{2}\right) \cdot \left(\frac{5}{2}\right) \cdot \frac{2}{3} - \frac{15 \cdot 15}{10} \)

(h) \( \frac{-8 \cdot -8}{4} \cdot \frac{1}{9} - \left(\frac{8}{2}\right) \cdot \left(\frac{8}{2}\right) \)

2. Koji od navedenih izraza ima rezultat jednak nuli?

(a) \( 8^2 \cdot -3.20 \cdot 1.90 - 1.5^2 \cdot \left(\frac{1}{2}\right)^2 \)
(b) \( 2.60 \cdot \frac{-3.50^2}{3.70} + \left(\frac{2}{3}\right)^2 \cdot 0.2 \)
(c) \( 40 \cdot \frac{-46^2}{2} + \frac{0.60^2}{3.70^2} \cdot \frac{3}{2} \cdot 8 \cdot \frac{-2.40^2}{12} \)
(d) \( (-8)^2 - \frac{-1}{9^2} - (-8)^2 \cdot 5^2 + 3^2 \cdot (-8)^2 - \left(\frac{-12}{2}\right)^2 \)

3. Dopuni tablicu.
x 5 2.10 6.60 9 9 4.60
y 5 2 2 3 15 10
z = x² - y²
4. Dopuni tablicu.
a b a² - b² (a - b)² a² + b² (a + b)²
8 4
9 8
2 7
5 6
-3 1
-0.40 -2
5. Izračunaj vrijednost izraza -x² + 3y² za zadane vrijednosti.

(a) \( x = 2, y = 1 \)
(b) \( x = -5, y = 3 \)
(c) \( x = 2, y = 3 \)
(d) \( x = -6, y = -4 \)

6. Izračunaj vrijednost izraza 2a² + b² za zadane vrijednosti.

(a) \( a = 3, b = -2 \)
(b) \( a = 4.10, b = 5 \)
(c) \( a = -1, b = 0 \)
(d) \( a = 0.60, b = 1 \)

(a) \( \left(-\frac{-3.20}{1.90}\right) \cdot \left(-\frac{-3.20}{1.90}\right) \cdot \left(\frac{1}{2.60}\right) \cdot \left(\frac{1}{2.60}\right) \)

(b) \( \left(\frac{3.50}{3.70}\right) \cdot \left(\frac{3.50}{3.70}\right) \cdot \frac{1}{2} \cdot \frac{40}{46 \cdot 46} \)

(c) \( \left(-\frac{0.60}{3.70 \cdot 3.70}\right) \cdot \left(-\frac{0.60}{3.70 \cdot 3.70}\right) - \left(-\frac{8}{2.40}\right) \cdot \left(-\frac{8}{2.40}\right) \)

(d) \( \frac{1}{8} \cdot \left(\frac{1}{9}\right) \cdot \left(\frac{1}{9}\right) - \frac{1}{8 \cdot 8} \)

(e) \( \frac{1}{5} \cdot \frac{1}{3 \cdot 3} \cdot \frac{8 \cdot 8}{12} \)

(f) \( \frac{5}{2.10} \cdot \left(\frac{6.60}{9}\right) \cdot \left(\frac{6.60}{9}\right) \cdot \frac{9}{4.60} \)

(g) \( \left(\frac{5}{2}\right) \cdot \left(\frac{5}{2}\right) \cdot \frac{2}{3} - \frac{15 \cdot 15}{10} \)

(h) \( \frac{-8 \cdot -8}{4} \cdot \frac{1}{9} - \left(\frac{8}{2}\right) \cdot \left(\frac{8}{2}\right) \)

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